Answer:
1). Xi=(4,0) , Yi=(0,−3)
A line passing through positive x intercept and negative y intercept will make acute angle with positive side of x axis. Hence slope is positive. As y intercept is 3 units from origin and x intercept is 4 units from origin, slope of line is 34. We already know y intercept so required equation is,
y=34x−3 ⟹
3x−4y−12=0
2). Sorry i dont know what the answer of number two is..
3). First Point: For
x
=
0
f
(
0
)
=
−
0
+
4
f
(
0
)
=
4
or
(
0
,
4
)
Second Point: For
x
=
4
f
(
4
)
=
−
4
+
4
f
(
4
)
=
0
or
(
4
,
0
)
We can next plot the two points on the coordinate plane:
graph{(x^2+(y-4)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y+x-4)(x^2+(y-4)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}
Explanation:
one way is to find the intercepts, that is where the graph
crosses the x and y axes
∙
let x = 0, in the equation for y-intercept
∙
let y = 0, in the equation for x-intercept
x
=
0
⇒
y
=
4
←
y-intercept
y
=
0
⇒
−
x
+
4
=
0
⇒
x
=
4
←
x-intercept
Plot the points
(
0
,
4
)
and
(
4
,
0
)
Draw a straight line through them for graph
graph{(y+x-4)((x-0)^2+(y-4)^2-0.04)((x-4)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}
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