Learning Task 1: Find the value of the expression given the value of the variables.
Answer:
1) 5x-3; x=7 → 32
2) 2x²-1 for x= -5 → 49
3) 4x²+3 for x=1/2 → 4
4) -12-3x² for x=0 → -12
5) 4x²-5y²/x-y for x=2 and y=2 → 4
Solution:
1) 5x-3; x=7
= 5x-3
= 5(7)-3
= (35)-3
= 32
2) 2x²-1 for x= -5
= 2x²-1
= 2(-5)²-1
= 2(25)-1
= (50)-1
= 49
3) 4x²+3 for x=1/2
= 4x²+3
= 4(1/2)²+3
= 4(1/4)+3
= (1)+3
= 4
4) -12-3x² for x=0
= -12-3x²
= -12-3(0)²
= -12-3(0)
= -12-(0)
= -12
5) 4x²-5y²/x-y for x=2 and y=2
= 4x²-5y²/x-y
= 4(2)²-5(2)²/(2)-(2)
= 4
It's Important to Understand about Substitution Method:
The substitution method includes replacing an expression from one equation for a variable in another equation. In order to apply this solution, one of the equations must have at least one independent variable. That's why replacement makes the most sense when the task already has an independent variable or at least one variable with a one-to-one relationship. Substitution is a wonderful opportunity whether you are interested in solving simple algebraic equations efficiently. It really does, even so, deal with various for those who make lots of calculation mistakes.
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