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x^3+ax^2+bx=c=0 has three real roots and they are consecutive terms of in an arithmetic progression. Show 2a^3+27c=9ab.

Sagot :

Answer:

(-222) - (-22)

\large{ \green{ \underline{ \blue{ \boxed{ \purple{ \tt{-200}}}}}}}

−200

2. (478) + (-840)

\large{ \green{ \underline{ \blue{ \boxed{ \purple{ \tt{-362}}}}}}}

−362

3. (-380) + (-217)

\large{ \green{ \underline{ \blue{ \boxed{ \purple{ \tt{-597}}}}}}}

−597

4.(-100) - (35)

\large{ \green{ \underline{ \blue{ \boxed{ \purple{ \tt{-135 }}}}}}}

−135

5. (550) - (-110)

\large{ \green{ \underline{ \blue{ \boxed{ \purple{ \tt{660}}}}}}}

660

\huge{ \rm{Explanation:}}

Step-by-step explanation:

When Adding integers, to add integers with the same sign, keep the same sign and add each number's exact value. To combine integers with different signs, retain the sign of the number with the greatest absolute value and subtract the smallest absolute value from the greatest.

And when your Subtracting integers, When one number is subtracted by an opposite number, the opposite will actually add to the first number. And when one number is subtracted by another number of the same sign it will subtract.

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