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A coffee shop is constructed midway between two commercial buildings. The coordinates of the first building are ( 20, 40) and the coordinates of the second building are ( 180, 120).

1. What are the coordinates of the point where the coffee shop will be constructed? Why do you think is the reason why it will be constructed at the midway between the two commercial buildings.
2. If each unit on the coordinate plane is equivalent to 3 meters, what is the distance between the two buildings?
3. How far would the coffee shop be from the first building? Second building? Explain your answer.


Sagot :

1. x= (x1 + x2)/2

x= (20+180)/2

x= 100

y= (y1 + y2)/2

y= (40 + 120)/2

y= 80

Coordinate of the coffee shop is (100, 80).

2. For distance: √[(x1 - x2)² + (y1 + y2)²]

√[(20-180)²+(40-120)²]

√[(-160)²+(-80)²]

√(25600+6400)

√(32,000)

√[(40²)(2²)(5)]

80√5 units

One unit = 3 meters

Real distance = (3 meters)(80√5)

The distance between the two buildings are 240√5 meters.

3. Since the coffee shop is midway and the distance between two buildings is 240√5 meters, the coffee shop is (240√5)/2 = 120√5 meters from both the building.