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Compute for the electronegativity difference of each compound then determine the polarity of the bond. Afterwards, draw the geometric sketch of each compound to identify the polarity of the molecules.

1. CH4
2. CO
3. SO2
4. H2O
5. HF​

Compute For The Electronegativity Difference Of Each Compound Then Determine The Polarity Of The Bond Afterwards Draw The Geometric Sketch Of Each Compound To I class=

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Answer:

1.) CH4

C=2.25 H=2.20

2.25 - 2.20 = 0.35

Bond polarity: 0.35

Tetrahedral non-polar

2.) CO

C=2.5 O=3.5

3.5 - 3.5 = 1.0 or 1

Bond polarity: 1.0 or 1

Polar Covalent Bond

3.) SO2

S=2.58 O=3.44

3.44 - 2.58 = 0.86

Bond polarity: 0.86

Polar Covalent Bond

4.) H2O

H=2.1 O=3.5

3.5 - 2.1 = 1.4

Bond polarity: 1.4

Bent Polar

5.) HF

H=2.2 F=4.0

4.0 - 2.2 = 1.8

Bond polarity: 1.8

Polar Covalent Bond

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