👤
Answered

1. How many moles are present in 100.0 g of Al?

Sagot :

SOLUTION:

There are 26.982 grams in 1 mole of Al.

[tex]\begin{aligned} \text{moles of Al} & = \text{100.0 g Al} \times \frac{\text{1 mol Al}}{\text{26.982 g Al}} \\ & = \boxed{\text{3.706 mol}} \end{aligned}[/tex]

Hence, there are 3.706 mol in 100.0 g of Al.

[tex]\\[/tex]

#CarryOnLearning

Go Training: Other Questions