Sagot :
Answer:
The maximum area can be derived by computing the first derivative which is dA/dx=50–2x. So the maximum length will occur when dA/dx=0 and thus x=y=25m. Perimeter of fenced area is P where P = 100 m. If area A is a square, then A = (P/4)^2 = 625 sq
Step-by-step explanation: