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How many moles of nitrogen molecules are required to produce 7.24 moles of ammonia, given an excess of hydrogen?​

Sagot :

Answer:

N2 + 3H2 ——————→ 2NH3

Mass of hydrogen = 7.25x10^[-4] g

Change it into moles

No of moles = (mass in grams)/atomic mass

Atomic mass of hydrogen = 2 g/mol

No of moles = 7.25x10^[-4]/2

No of moles of hydrogen = 3.62x10^[-4]

According to equation

3 moles of hydrogen produce NH3 = 2 mol

1 moles of hydrogen produce NH3 = 2/3

1 moles of hydrogen produce NH3 = 0.67

3.62x10^[-4] mol hydrogen produce NH3 = 0.67 x 3.62x10^[-4] = 2.42x10^[-4]

So no of moles of NH3 = 2.42x10^[-4]

Change it into molecules

No of molecules = (no of moles)x Avogadro's number

No of molecules = 2.42x10^[-4] x 6.02x10^23

No of molecules of NH3 = 14.52x10^19

pls braineast