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Withermelongo
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Giver Kle CUTE with diagonasi and 27 intenect at point X Prove: UF the perpendicular biector of 7. 3. uc=uT; CE = TE Statements 1 2.UCUT CE = TE Reasons 1.Given 2. 3 #aline contains two points each of which is equidistant from the endpoints of a segment. then the line is perpendicular bisector of the segment​

Giver Kle CUTE With Diagonasi And 27 Intenect At Point X Prove UF The Perpendicular Biector Of 7 3 UcuT CE TE Statements 1 2UCUT CE TE Reasons 1Given 2 3 Aline class=

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Giver Kle CUTE with diagonasi and 27 intenect at point X Prove: UF the perpendicular biector of 7. 3. uc=uT; CE = TE Statements 1 2.UCUT CE = TE Reasons 1.Given 2. 3 #aline contains two points each of which is equidistant from the endpoints of a segment. then the line is perpendicular bisector of the segment

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