Sagot :
Answer:
1.)A.)x=7
=since side HE is congruent to side OR
we must say side HE is equal to side OR.
given:HE=2x and OR=x+7
SOLUTION:
2x=x+7
2x-x=7 combined like terms and solve it
x=7
B.)HE=14
=Since we have the value of x which is 7,we will just distribute it in the given formula for finding HE.
given:HE=2x
SOLUTION:HE=2(7)
=14
2.)A.)y=3
B.)=17°
=<HER is congruent to <ROH so <HER=<ROH
5y-3=2y+9
5y-2y=9+3 combinedlike terms and solve it
3y=12
3y÷3=12÷3 divide both sides with the given variables
y=4
<ROH=2y+9
2(4)+9apply distributive property
8+9
<ROH=17°