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Write the rule used for each sequence, then write the missing term.

1. 3, 7, 11, 15,

2. 5, 9, 17,33,

3. 20, 12, 8, 6,

4. 2, 8, 26, 80,

5. 36, 69, 135, 267,​


Sagot :

Answer:

3,7,11,15,__

As it can be seen as, every term in this series is incremented by 4.

\begin{gathered}3+4=7\\7+4=11\\11+4=15\\15+4=19\end{gathered}

3+4=7

7+4=11

11+4=15

15+4=19

Hence, 19 will continue the series.

5,9,17,33,\_\_5,9,17,33,__

As it can be seen as, every term in this series is multiplied by 2 and then subtracted by 1.

\begin{gathered}5\times2-1=9\\9\times2-1=17\\17\times2-1=33\\33\times2-1=65\end{gathered}

5×2−1=9

9×2−1=17

17×2−1=33

33×2−1=65

Hence, 65 will continue the series.

20,12,8,6,\_\_20,12,8,6,__

As it can be seen as, every term in this series subtracts the power of 2.

\begin{gathered}20-2^3=12\\12-2^2=8\\8-2^1=6\\6-2^0=5\end{gathered}

20−2

3

=12

12−2

2

=8

8−2

1

=6

6−2

0

=5

Hence, 5 will continue the series.

2,8,26,80,\_\_2,8,26,80,__

As it can be seen as, every term in this series is multiplied by 3 and then added by 2.

\begin{gathered}3\times3+2=8\\8\times3+2=26\\26\times3+2=80\\80\times3+2=242\end{gathered}

3×3+2=8

8×3+2=26

26×3+2=80

80×3+2=242

Hence, 242 will continue the series.

36,69,135,267,\_\_36,69,135,267,__

As it can be seen as, every term in this series is multiplied by 2 and then subtracted by 3.

\begin{gathered}36\times2-3=69\\69\times2-3=135\\135\times2-3=267\\267\times2-3=531\end{gathered}

36×2−3=69

69×2−3=135

135×2−3=267

267×2−3=531

Hence, 531 will continue the series.

Step-by-step explanation:

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