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Find the number of permutations if four 1,000 peso bill, two 100 peso bill,

three 50 peso bill and two 20 peso bill be arranged in a wallet??​


Sagot :

69300 permutations

✎4 - 1000 peso bill

2- 100 peso bill

3 - 50 peso bill

2 - peso bill

n1 = 4, n2 = 2, n3= 3, n4 = 2

n= 11 because 4+2+3+2

p= 11!/ 4!2!3!2!

p = 11•10•9•8•7•6•5•4! / 4!2!3!2!

cancel the two 4!

p = 1663200/2 • 3!2!

p= 831600/3!2! (divide sa 3!)

p= 138600/2!

p= 69300

! - read as "factorial"

p - permutation

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Hope it helps<33

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-angela8689-