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A man standing at the top of a building 100 m high notes that the angle of depression of a traffic junction below is 20⁰ .How far is the traffic junction from the foot of the building to the nearest hundredths of a meter​

Sagot :

Answer:

274.75 m

Step-by-step explanation:

SOHCAHTOA method

let x be the unknown distance

tan (20deg) = X/ 100m

x = 274. 7477419 or 274.75 m