Answer:
8y^3-60y^2+150y-125
Step-by-step explanation:
(2y−5)*(2y−5)*(2y−5)
=(2y+−5)(4y2+−20y+25)
=(2y)(4y2)+(2y)(−20y)+(2y)(25)+(−5)(4y2)+(−5)(−20y)+(−5)(25)
=8y3−40y2+50y−20y2+100y−125
=8y3−60y2+150y−125
