SOLUTION:
Based on the balanced chemical equation, 2 moles of C₂H₆ is stoichiometrically equivalent to 7 moles of O₂.
The molar masses of C₂H₆ and O₂ are 30.07 g and 31.998 g, respectively.
[tex]\begin{aligned} \text{mass of} \: \text{O}_2 & = \text{11.2 g} \: \text{C}_2\text{H}_6 \times \frac{\text{1 mol} \: \text{C}_2\text{H}_6}{\text{30.07 g} \: \text{C}_2\text{H}_6} \times \frac{\text{7 mol} \: \text{O}_2}{\text{2 mol} \: \text{C}_2\text{H}_6} \times \frac{\text{31.998 g} \: \text{O}_2}{\text{1 mol} \: \text{O}_2} \\ & = \boxed{\text{41.7 g}} \end{aligned}[/tex]
Hence, 41.7 g of O₂ is required to react with 11.2 g of C₂H₆.
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