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How many ways may 5 students be elected from a club with 20 members?

Sagot :

Answer:

15,504 ways

Step-by-step explanation:

This problem involves Combination because order does not matter therefore we use the formula: nCr

where

n = 20

r = 5.

Substitute:

20C5 = 15504

15, 504 ways

those "!" are factorials. If someone says 20!, that is:

20! = 20×19×18×17×16 . . .×3×2

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