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If you were to take a volleyball scuba diving with you what would be its new volume if it started at the surface with a volume of 2.00L, under a pressure of 752.0 mmHg and a temperature of 20.0°C? On your dive you take it to a place where the pressure is 2943 mmHg, and the temperature is 0.245°C.

(with solution po sana, ty) ​

Sagot :

Kimyeriigo

Answer:

The new volume of the ball will be 0.48 L

Given:

P1 = 752. 0 mmHg

P2 = 2943 mmHg

V1 = 2.00 L

V2 = X

(change to kelvin)

T1 = 20°c + 273 = 293 K

T2 = 0.245 °c + 273 = 273.245 K

Unknown: V2

Equation: P1 V1 / T1 = P2 V2 / T2

Solution:

(752.0 mmHg) (2.00 L) / 293 K = (2943 mmHg) (x) / 273.245 K

= (1504) / 293 K = (2943 mmHg) (x) / 273.245 K

(Cross Multiplication)

= (1504) (273.245 K) / (293 K) (2943 mmHg) (x)

= 410 960.48 / 862 299 (x)

X = 0.4765 L

V2 = 0.48 L

Answer:

The new volume of the ball is 0.48 L

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