👤
Answered

perform the indicated operation
(Kahit Yung 3,4,5 nalang Po thxxxx)​

Perform The Indicated OperationKahit Yung 345 Nalang Po Thxxxx class=

Sagot :

HakuYukigo

Answer:

3. (3x² - 5x  + 2) (x² + 2x)

Solution:

(3x²) (x²) = [tex]3x^{4}[/tex]

(3x²) (2x) = [tex]6x^{3}[/tex]

(-5x) (x²) = [tex]-5x^{3}[/tex]

(-5x) (2x) = [tex]-10x^{2}[/tex]

(2) (x²) = [tex]2x^{2}[/tex]

(2) (2x) = [tex]4x[/tex]

Then arrange them:

[tex]3x^{4} + 6x^{3}+-5x^{3}+-10x^{2}+2x^{2}+4x[/tex]

Answer: [tex]\boxed{3x^{4} + x^{3}+-8x^{2}+4x}[/tex]

4. [tex]\frac{24a^{6} }{6a^{5} }[/tex]

Solution:

[tex]\frac{24}{6}=4[/tex]

[tex]a^{6-5} =a[/tex]

Then arrange them:

Answer: [tex]\boxed{4a}[/tex]

5. [tex]\frac{84x^{6}y^{4}z^{3} }{3x^{3}y^{3}z }[/tex]

Solution:

[tex]\frac{84}{3}=28[/tex]

[tex]x^{6-3} =x^{3}[/tex]

[tex]y^{4-3} =y[/tex]

[tex]z^{3-1} =z^{2}[/tex]

Then, arrange them:

Answer: [tex]\boxed{28x^{3} yz^{2}}[/tex]

MasterOfMathProblemgo

✒️POLYNOMIAL

[tex] \tt \: 3.)(3x {}^{2} - 5x + 2)(x {}^{2} + 2x) \\ \tt \: 3x {}^{2} \times x {}^{2} + 3x {}^{2} \times 2x - 5x(x {}^{2} + 2x ) + 2(x {}^{2} + 2x) \\ \tt \: \: 3x {}^{2} \times x {}^{2} + 3x {}^{2} \times 2x - 5x \times 2x + 2(x {}^{2} + 2x) \\ \tt \: 3x {}^{4} + 3x {}^{2} \times 2x - 5x \times x {}^{2} - 5x \times 2x + 2x {}^{2} + 2 \times 2x \\ \tt \: 3x {}^{4} + 6x {}^{3} - 5x \times x {}^{2} - 5x \times 2x + 2x {}^{2} + 2 \times 2x \\ \tt \: 3x {}^{4} + x {}^{3} - 8x {}^{2} + 4x \\ \tt \: 3x {}^{4} + (6x {}^{3} - 5x {}^{3} ) + ( - 10x {}^{2} + 2x {}^{2} ) + 4x \\ \tt \red{3x {}^{4} + x {}^{3} - 8x {}^{2} + 4x} \: \\ \\ \\ \tt \: 4.) \frac{24a {}^{6} }{6a {}^{5} } = \frac{4a {}^{6} }{a {}^{5} } = \red{4a} \\ \\ \\ \\ \tt \: 5.) \frac{84x {}^{6}y { }^{ - 6} z {}^{2} }{3x {}^{3} y {}^{2}z } = \frac{28x {}^{6}z {}^{2} }{x {}^{3} y {}^{2}zy {}^{6} } = \frac{28x {}^{3} z {}^{2} }{y {}^{2}zy {}^{6} } = \red{\frac{28x {}^{3} z}{y {}^{8} } }[/tex]

#CarryOnLearning

[tex]\qquad\qquad\qquad\qquad\qquad\qquad\tt{03-03-2022} \\ \qquad\qquad\qquad\qquad\qquad\qquad\tt{11:30\: am}[/tex]

Go Training: Other Questions