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permutation problems a basketball team has thirteen players , and the coach must choose his starting line up: the five players who will start the game . how many different starting line ups can coach choose​

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Jamqzgo

Answer:

154440 ways

Step-by-step explanation:

[tex]\frac{13!}{13 - 5}[/tex] = [tex]\frac{13!}{8!}[/tex] = 154440

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