Answer:
The number of permutations with identical objects is
[tex]N=\frac{r!}{r_{1}!r_{2}!r_{3}!...r_{k}!}[/tex]
In this problem, [tex]r=8+4+2=14[/tex], [tex]r_{1} =8[/tex], [tex]r_{2} =4[/tex] and [tex]r_{3} =2[/tex]
Therefore, the answer is:
[tex]N=\frac{14!}{8!4!2!} =45045[/tex]
