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Ihave5daysgo
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A roller coaster's velocity at the top of a hill is 10 m/s. Two seconds later it reaches the bottom of the hill with a velocity of 25 m/s. What was the acceleration of the coaster?

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MysticalGlimpsego

Hello!

Formula:

[tex] \longmapsto \large A = \frac{(v_f - v_i)}{t} [/tex]

  • A - Acceleration
  • Vf - Final Velocity
  • Vi - Initial Velocity
  • t - Time

Given:

  • Vf - 25m/s
  • Vi - 10m/s
  • t - 2s

Solution:

[tex] \longmapsto \large A = \frac{(25m/s - 10m/s)}{2s} [/tex]

[tex] \longmapsto \large A = \frac{15m/s}{2s} [/tex]

[tex] \longmapsto \large A = 7.5m/s {}^{2} [/tex]

Therefore,the accelaration of the coaster is 7.5m/s².

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