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square of a number Eight less than a number, squared​

Sagot :

Answer:

The key to verbal problem is to translate the words into a mathematical expression.

"Eight more then the square of a number": the number is unknown thus it is "x". The square of the number is x^2.

Eight more is 8+x^2.

So 8+ x^2 "is the same as six times the number". Our number is "x" and six times of the number is 6x.

Therefore our equation is: 8 + x^2 = 6x

Subtracting 6x from both sides of the equation is: 8 + x^2 - 6x = 0

Rearranging it x^2 - 6x + 8 =0

This can be solved by the quadratic equation: ( -b +- (b^2 - 4ac)1/2)/ 2a for ax^2 + bx + c =0

(6+-(6*6 - 4*1*8)1/2/2*1

(6+-(36-32)1/2)/2

(6+-(4)1/2)/2

The two solutions are:

(6+2)/2 and (6-2)/2

4 and 2

Alternatively one can recognize that the equation x^2 - 6x + 8 = (x-4)(x-2) = 0 so x = 4 or x = 2

Therefore there are two numbers that satisfies this question 4 and 2.

Step-by-step explanation:

Hope it helps pa brainliest nga po pala