Step 1: Calculate the number of moles of solute (MgCl₂).
Note that the molar mass of MgCl₂ is 95.21 g/mol.
[tex]\begin{aligned} \text{moles of solute} & = \frac{\text{mass of solute}}{\text{molar mass of solute}} \\ & = \frac{\text{45.7 g}}{\text{95.21 g/mol}} \\ & = \text{0.480 mol} \end{aligned}[/tex]
Step 2: Calculate the molality of solution.
[tex]\begin{aligned} \text{molality} & = \frac{\text{moles of solute}}{\text{mass of solvent}} \\ & = \frac{\text{0.480 mol}}{\text{2.40 kg}} \\ & = \text{0.200 mol/kg} \\ & = \boxed{0.200 \: m} \end{aligned}[/tex]
Hence, the molality of the solution is 0.200 m.
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