Answer:
let 3rd side be of x cm
sum of 2 sides of a ∆ > 3rd side
therefore 6 + 10 > x
x < 16
so x must be less than 16
similarly 6 + x > 10
x > 4
so x must be greater than 4
therefore the measure of the 3rd side should be between 4 and 16
Step-by-step explanation:
