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Calculate the force of attraction between 250 kg car and 112 kg motorcycle parked and separated with a distance of 5.0 m? *​

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Sagot :

BrainlyMateego

ANSWER

Let us use the formula for finding the force of attraction.

  • [tex] \tt F_n = \frac{m_1 \: m_2}{ {r}^{2} } [/tex]

It stands for,

Fn = Force of newton

m1 = mass of object 1

m2 = mass of object 2

r = distance between the two objects

[tex]\: [/tex]

  • [tex] \tt F_n = \frac{(250kg)(122kg)}{5.0m {}^{2} } [/tex]

  • [tex] \tt F_n = \frac{30500 \: kg}{25 \: m} [/tex]

  • [tex] \tt F_n = 1220 \: N[/tex]

Therefore, the force of attraction of a car and motorcycle is 1,220 Newtons.

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