👤

A sample of 50 Grade 11 students’ ages was obtained to estimate the mean age of all
Grade 11 students. The sample mean is 16.5 years, and the standard deviation is 1.60 at 95% level of
confidence


Sagot :

n=11

x

ˉ

=17.3

σ

2

=18

σ=4.24

The point estimate of the population parameter

\mu = 17.3 \\ α = 1 -0.95 = 0.05 \\ α/2 = 0.025 \\ Z_{0.025} = ±1.96μ=17.3

α=1−0.95=0.05

α/2=0.025

Z

0.025

=±1.96

Confidence interval for the population parameter:

\mu ± Z_{0.025} \times \frac{4.24}{\sqrt{11}} \\ 17.3 ± 1.96 \times 1.278 \\ 17.3 ± 2.50μ±Z

0.025

×

11

4.24

17.3±1.96×1.278

17.3±2.50

The 95% confidence interval for the population parameter: (14.8, 19.8)

α = 1 -0.99 = 0.01 \\ α/2 = 0.005 \\ Z_{0.005} = ±2.58α=1−0.99=0.01

α/2=0.005

Z

0.005

=±2.58

Confidence interval for the population parameter:

\mu ± Z_{0.005} \times \frac{4.24}{\sqrt{11}} \\ 17.3 ± 2.58 \times 1.278 \\ 17.3 ± 3.29μ±Z

0.005

×

11

4.24

17.3±2.58×1.278

17.3