Answer:
Solution
Correct option is B)
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Since, total balls = 20
(i) odd numbers from 1 to 20 are:
1,3,5,7,9,11,13,15,17,19
no. of balls bearing odd numbers = 10
favorable outcomes= 10
probability = \frac{10}{20} = \frac{1}{2}probability=
20
10
=
2
1
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(ii) number divisible by 2 or 3 from 1 to 20 are:
2,3,4,6,8,9,10,12,14,15,16,18,20
no. of balls bearing number divisible by 2 or 3 = 13
favorable outcomes= 13
probability \frac{13}{20}probability
20
13
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(iii) prime numbers from 1 to 20 are:
2,3,5,7,,11,13,17,19
no. of balls bearing prime number = 8
favorable outcomes= 8
probability = \frac{8}{20} = \frac{2}{5} < /li > < li >probability=
20
8
=
5
2
</li><li>
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(iv) No. of balls bearing number not divisible by 10 = 18
favorable outcomes= 18
probability = \frac{18}{20} = \frac{9}{10}probability=
20
18
=
10
9
#CARRY ON LEARNING
– zhen ❦
