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An athlete throws a javelin with a velocity of 28.2 m/s at 42.5 degrees, how far will the javelin go?

Sagot :

80.76m

Solution: =28.2m/s

=42.5⁰

=(28.2)².2 Sin 42.5⁰. Cos 42.5⁰/9.81

=792.21/9.81

So hence javelin will go 80.76m fast.

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