Answer:
YES
The period of an elliptical orbit (the time required for one revolution) is computed from Kepler's second law: the radius vector sweeps out equal areas in equal times. The constant “areal rate” swept out by the radius vector is dA/dt = h/2, where the constant h is the magnitude of the angular momentum vector.
In astrodynamics or celestial mechanics, an elliptic orbit or elliptical orbit is a Kepler orbit with an eccentricity of less than 1; this includes the special case of a circular orbit, with eccentricity equal to 0.
Explanation:
