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Answered

How many grams of pure acid must be added to 36 grams of a 10% solution of acid to make a 40% solution?

Sagot :

x=grams of pure acid.
pure acid formula .20(40)+1.00(x)=.36(40+x)
8+x=14.4+.36x
0.64x=6.4
x=10 gms.
10 is 1/5 of the final amount
36% is 1/5 of the way between 20% and 100%
19dollarstorgo

The Answer:

18 grams

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