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in the sequence 12 19 26 33 40 find the sum of the first 50 terms.

Sagot :

Answer:

Arithmetic Sequence:

[tex]S=\frac{n}{2}(2a_{1}+(n-1)d)[/tex]

1. To determine difference (d):
   d = 40-33 = 7
         33-26 = 7

          26-19 = 7

           19-12 = 7

2. To determine number of terms (n):

                d = 50 terms

Substitute,

[tex]S=\frac{n}{2}(2a_{1}+(n-1)d)[/tex]

[tex]S=\frac{50}{2}(2(12)+(50-1)7)[/tex]

[tex]S=9175[/tex]   → Ans.