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Three times the first of three consecutive odd integers is three more than twice the third. find the third integer

Sagot :

AkiAintScaredgo
  • First integer is num – 2 i.e. 13 – 2 = 11. ✍

  • Third integer is num + 2 i.e. 13 + 2 = 15.✍

  • So, 11, 13, and 15 are the three consecutive odd integers.✍
First integer=n
Second integer=n+2
Third integer=n+4

Three times the first of three consecutive integer:
3n

is
=

Three more than twice the third integer
2(n+4)+3

Combine them all to form an equation.
3n=2(n+4)+3
Now solve for n
3n=2n+8+3
3n=2n+11
n=11

Third integer=n+4=11+4=15

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