Sagot :
SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} P_2 & = \text{1.50 atm = 1140 torr} \\ V_2 & = \text{250 mL} \\ P_1 & = \text{900 torr} \end{aligned}[/tex]
Step 2: Calculate the initial volume by using Boyle's law.
[tex]\begin{aligned} V_1 & = \frac{P_2V_2}{P_1} \\ & = \frac{(\text{1140 torr})(\text{250 mL})}{\text{900 torr}} \\ & = \boxed{\text{317 mL}} \end{aligned}[/tex]
Hence, the initial volume of fluorine gas was 317 mL.
[tex]\\[/tex]
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