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What is the kinetic energy of a 0.01lbm bullet travelling 2000 ft/s relative to the barrel of the gun it has left? *

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SenLangPargo

[tex]\large \rm {\color{blue}{Question:}}[/tex]

What is the kinetic energy of a 0.01lbm bullet travelling 2000 ft/s relative to the barrel of the gun it has left?

[tex]\small \rm {\color{red}{Answer:}}[/tex]

K.E = 20,000 ft/s J

Explanation:

To find the K.E/Kinetic Energy you have to use this formula.

  • K.E = ½mv²

How to solve?

1.)Identify the given

  • Given

Mass of the bullet is 0.01 lbm, and the velocity/speed of the bullet is 2000 ft/s.

2.)Solve

  • K.E = ½mv²
  • K.E =½0.01 lbm (2,000 ft/s)²
  • K.E =½ 0.01 lbm (4,000,000 ft/s)
  • K.E = ½40,000 lbmft/s
  • K.E = 20,000 lbmft/s

Therefore, the Kinetic Energy of the bullet is 20,000 lbmft/s.

Hope it helps :D

By : セン

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