Sagot :
Answer:
(3x+1)/(4-2x)
Step-by-step explanation:
f(x)= (4x-1)/2x+3
To find the inverse function f(x)^-1 we will assume:
y=(4x-1)/(2x+3)
==> multiply by 2x+3
==> y(2x+3)= 4x-1
==> 2yx+3y=4x-1
==> 3y+1= 4x-2yx
==> 3y+1= x(4-2y)
==> x= (3y+1)/(4-2y)
==> f(x)^-1= (3x+1)/(4-2x)