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The perimeter of a parallelogram is 34 cm. if a diagonal is 1 cm less than its length and 8 cm more than its width, what are the dimensions of this parallelogram?

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Answer:

(Assuming the parallelogram is a rectangle)

Perimeter= 2Width+2Length=34 cm

2W+2L=34--------eq 1

[tex]L-1=W+8[/tex]-------eq 2

solving eq 1 & 2:

L=13 cm

W=4 cm

13 cm x 4 cm

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