Sagot :
[tex] \bold{Problem:} [/tex]
Claculate the density, specific weight and specific volume of chlorine gas at 25°C and under a pressure of 600 KPa absolute.The gas constant R for chlorine is 117 N-m/Kg-k.
[tex] \bold{Solution:} [/tex]
1. Use this equation to get the density
- [tex]p = \frac{p}{RT} [/tex]
- [tex]p = \frac{600}{(117) \: (25 + 273)} [/tex]
- [tex]p = 17.2 \: Kg /{m}^{3} [/tex]
2. Equation Gives the Specific Weight
- [tex]w = pg[/tex]
- [tex]w = 17.2 \: \times \: 9.81 \: = 168.732N/ {m}^{3} [/tex]
3. The Specific Volume
- [tex]v = \frac{1}{p} [/tex]
- [tex]v = \frac{1}{17.2} [/tex]
- [tex]v = 0.058 {m}^{3}/Kg[/tex]