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Kei5889go
Answered

Ano po sagut dito mga boss​

Ano Po Sagut Dito Mga Boss class=

Sagot :

KieshaHermosogo

SOLUTIONS :

  • SUBSTITUTE

[tex]substitute \: x = 4 \\ f(4) = \sqrt{ {4}^{2} - 4 \times 4 + 1} [/tex]

  • CALCULATE

[tex]f(4) = 16 - 4 \times 4 + 1 \\ f(4) = 16 - 16 + 1 \: \: \: \: \\ f(4) = \sqrt{1} [/tex]

QUESTION A = F(4) = 1

  • SUBSTITUTE

[tex]substitute \: x = 1 + a \\ f(1 + a) = ( {1 + a}^{2} ) - 4(1 + a) + 1[/tex]

  • CALCULATE

expanding the expression using

  • (a ± b)²= a² ± 2ab + b²

[tex]f(1 + a) = 1 + 2a + {a}^{2} - 4(1 + a) +1 \\ f(1 + a) = 2 + 2a + {a}^{2} - 4(1 + a) \\ ... \\ f(1 + a) = \sqrt{2 + 2a + {a}^{2} - 4 - 4a} \\ f(1 + a) = \sqrt{ - 2 - 2a + {a}^{2} } \\ f(1 + a) = \sqrt{ - (2 + 2a - {a}^{2} } \\ f( 1 + a) = \sqrt{ - ( - {a}^{2} + 2a + 2)} [/tex]

QUESTION B = F(1+a) = √a² - 2a - 2

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