QUADRATIC FORMULA
Hi, can someone solve this

Answer:
The solution or roots are x = 3 and x = 3.
Step-by-step explanation:
x² - 6x + 9 = 0
a = 1, b = -6, c = 9
Using Quadratic Formula: ±
[tex]x = \frac{ \:- b± \sqrt{ {b}^{2} - 4ac} }{2a}
\\ [/tex]
[tex]x = \frac{ - ( - 6)±\: \sqrt{( - 6 {)}^{2} - 4(1)(9)} }{2(1)} [/tex]
[tex]x = \frac{ 6 ±\: \sqrt{36 - 36} }{2} [/tex]
[tex]x = \frac{6 ± \: 0 }{2} [/tex]
[tex] x_{1} = \frac{6 + 0}{2} = 3[/tex]
[tex] x_{2} = \frac{6 - 0}{2} = 3[/tex]