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In the sequence 4, 5, 9, 14, ..., the 7th term is 61.
Identified Error: | Correction of the
Error:



Explanation of correction:​


Sagot :

Answer:

Arithmetic Sequence

an = last term of the nth value

a1 = first term

n = number of terms

d = difference

GIVEN

a1=4

d=5

SOLVING

a6 = 4+(6-1)5

=4+(5)5

=4+25

=29

a7 = 4+(7-1)5

= 4+(6)5

=4+30

=34

a8 = 4+(8-1)5

=4+(7)5

=4+35

=39

a9 = 4+(9-1)5

= 4+(8)5

=4+40

=44

a10 = 4 + ( 10 - 1 ) 5

= 4 + (9) 5

= 4 + 45

= 49

Step-by-step explanation: