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Solve by Completing the square

x²-8x=-7​


Sagot :

[tex]{ \huge\text{ Answer}} [/tex]

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Solve by Completing the square

x² - 8x = -7.

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[tex]\sf{{ x² - 8x = -7 }}[/tex]

[tex]\sf{{ {x}^{2} - 8x + 7 = 0 }}[/tex]

[tex]\sf{{ {x}^{2} - 7x - x + 7 = 0 }}[/tex]

[tex]\sf{{ x(x - 7) - (x - 7) = 0 }}[/tex]

[tex]\sf{{ (x - 7)(x - 1) = 0 }}[/tex]

[tex]\sf{{ x - 7 = 0 \: or \: x - 1 = 0 }}[/tex]

[tex]\large \rm Final \: Answer:[/tex]

  • [tex]\sf{{ x = 7 \: or \: x = 1 }}[/tex]

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