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determine whether or not each of the following pts is solution of a quadratic inequality
[tex]y \leqslant 2 {x}^{2} + 3x \: - 5[/tex]

1. A(-1,6)
2. B(2,9)
3. C(1,-4)
4.D(0,0)
5.E(-2,-5)​


Sagot :

Answer:

You can do it algebraically by substituting and checking if the inequality is satisfied. You can also do it the graphical way:

The red region is the region where the inequality satisfies.

Plot these:

  1. A(-1,6)
  2. B(2,9)
  3. C(1,-4)
  4. D(0,0)
  5. E(-2,-5)​

You can see that A and D lie in the region inside the parabola, so they are not a solution.

Rest all are solutions to the inequality.

[tex]\frak Answer:[/tex]

  1. A(-1,6)  - It is not a solution.
  2. B(2,9)  - It is a solution.
  3. C(1,-4)  - It is a solution.
  4. E(-2,-5)​ - It is a solution.
  5. D(0,0)  - It is not a solution.

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