[tex](x+y)(x^2-xy+y^2)[/tex]
The sum of two cubes can be factored using the rule: [tex]a^3 + b^3 = (a+b)(a^2-ab+b^2)[/tex]
[tex]x^3+y^3 = (x+y)(x^2-xy+y^2)[/tex]
Therefore the answer is [tex](x+y)(x^2-xy+y^2)[/tex]
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