Answer:
[tex]x = 2,[/tex] [tex]x=\frac{2}{5}[/tex]
Solution:
All equation in the form of [tex]ax^2 + bx + c[/tex] can be solved using quadratic formula [tex]x = \frac{-b±\sqrt{b^2-4ac} }{2a}[/tex]
Referring to the given equation, a = 5, b = -12 and c = 4
Substitute the given value
[tex]x = \frac{-(-12)±\sqrt{-12^2-4(5)(4)} }{2(5)}[/tex]
[tex]x = \frac{12±\sqrt{144-80} }{10}[/tex]
[tex]x = \frac{20}{10} , x = \frac{4}{10}[/tex]
Therefore the answer is 2, 2/5
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