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The perimeter of a rectangle is 64 ft. The length of the rectangle is 3 ft less than 4 times

the width. What are the dimensions of the rectangle?​


Sagot :

Answer:

L = 25

W = 7

Solution:

Perimeter of rectangle = 2(L+W)

2(L+W) = 64

L = 4W - 3

Substitute W for L

2(4W-3+W) = 64

8W + 2W - 6 = 64

10W - 6 = 64

Add 6 to both sides

10W = 70

W = 70/10 = 7

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