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Math

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the length of a rectangular sign is 2 meters less than 3 times its width. if the area of the rectangular sign us 40m², what is the width

Sagot :

Tierthugo Tierthugo

Answer:

y = 3x -2m; 40m² = xy; x = 40m²/y

40m² = xy

40m² = x(3x -2m)

40m² = 3x² -4m²

40m² +4m² = 3x² -4m² +4m²

44m²/3 = 3x²/3

√(44m²/3) = √x²

x = √(44m²/3)

y = 3x -2m

y = 3{√(44m²/3)} -2m

sorry, can't compute the roots. I hope you could solve the rest.

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