Answer:
ABCD is a rectangle with length AB= √8
cm and breadth AD= √2cm
2cmSince opposite sides of rectangle are equal
2cmSince opposite sides of rectangle are equal⇒AD=BC= 2 cm
Now each angle in a rectangle is at 90 o
each angle in a rectangle is at 90 o
each angle in a rectangle is at 90 o ⇒∠DCB=∠CBA=∠BAD=
∠ADC=90 o
∠ADC=90 o
∠ADC=90 o Now In ΔCAB
∠ADC=90 o Now In ΔCABAC is the hypotenuse, AB is the base and CB is the altitude by Pythagoras theorem.
∠ADC=90 o Now In ΔCABAC is the hypotenuse, AB is the base and CB is the altitude by Pythagoras theorem.(AC) 2 =(CB) 2+(AB) 2
∠ADC=90 o Now In ΔCABAC is the hypotenuse, AB is the base and CB is the altitude by Pythagoras theorem.(AC) 2 =(CB) 2+(AB) 2
∠ADC=90 o Now In ΔCABAC is the hypotenuse, AB is the base and CB is the altitude by Pythagoras theorem.(AC) 2 =(CB) 2+(AB) 2 (AC) 2 =( 2 ) 2 +( 8 ) 2
) 2
) 2 (AC) 2 =2+8
) 2 (AC) 2 =2+8(AC) 2 =10
) 2 (AC) 2 =2+8(AC) 2 =10AC= 10cm.
