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Vergiesevilla4go
Answered

A lader 13 meter long is placed is on the groundia is such a way that is the touches the top of the vertical wall 12 meters high find the distance of the foot of the lader from the bottom of the wall

Sagot :

Kathreentordilgo

Answer:

Solve with pythagorean theorem

c^2=a^2+b^2

c-measure of the laddee

b-measure of the vertical wall from the top of the ladder to the ground

a-distance of the foot of the ladder to the bottom of the wall.

c=13m

b=12m

a=?

c^2=a^2+b^2

13^2=a^2+12^2

13^2-12^2=a^2

169-144=a^2

√25=√a^2

5 m=a----- final answer

The distance of the foot of the ladder to the bottom of the wall is 5 m high

Step-by-step explanation:

136668150104go

Answer:

c^2=a^2+b^2

13^2=a^2+12^2

13^2-12^2=a^2

169-144=a^2

√25=√a^2

Step-by-step explanation:

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