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Chemistry

Answered

The pressure in a sealed can of gas is 215kPa when it sits at room temperature (30°C). If the can is warmed to 60°C, what will the new pressure inside the can be?

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Answer: 236 kPa

Explanation:

P1T2=P2T1

(215kPa)(60+ 273.15K)=(P2)(30+273.15K)

P2=236.2765957 kPa

P2= 236 kPa

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