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1.) Find the present value of ₱14,850.00 due in 4 years if the interest rate is 5% compounded monthly.

2.) How many years will it take for ₱20,000.00 to become ₱28,000.00 at 12% compounded annually?

3.) ₱15,000.00 is invested for 1 year at. 7% compounded semi-annually. find the future value?

4.) ₱15,000.00 is invested for 1 year at. 7% compounded semi-annually. how much is the interest earned?​


Sagot :

Answer:

2.97 years

Step-by-step explanation:

A=P(1+r)^n

A=20,000(1+0.12)^n

28,000=20,000(1+0.12)^n

[tex] \frac{28000}{20000} = \frac{20000(1 + 0.12) {}^{n} }{20000} [/tex]

[tex](1.4) = (1.12) {}^{n} [/tex]

[tex] log(1.4) = n log(1.12) [/tex]

[tex]0.146 = n(0.04922)[/tex]

[tex] \frac{0.146}{0.04922} = \frac{0.04922n}{0.04922} [/tex]

[tex]2.97 = n[/tex]

THAT WAS NO. 2

=It will take 2.97 years for 20,000 to become 28,000 at 12% interest compounded annually